How many ml of 1 (M) $H_{2} S O_{4}$ is required to neutralise 10 ml of 1 (M) NaOH solution

2.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 5
$(H_{2} S O_{4}) \frac{M_{1} V_{1}}{n_{1}} = \frac{M_{2} V_{2}}{n_{2}} (N A O H)$
$\frac{1 \times V_{1}}{1} = \frac{1 \times 10}{2}; V_{1} = 5 m l$

Suggest Corrections

Similar questions

m L

1 M H_{2} S O_{4}

10 m L

1 M N a O H

H_{2} S O_{4}

How many milli litres of 1M H₂SO₄ will be neutralised by 10mL of 1M NaOH solution?

M / 20 H C l

20 m l

M / 10 N a O H

{H_{2} S O}_{4}

Join BYJU'S Learning Program