How many ml of 1 (M) $H_{2} S O_{4}$ is required to neutralise 10 ml of 1 (M) NaOH solution

2.5

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Solution

The correct option is B 5
$(H_{2} S O_{4}) \frac{M_{1} V_{1}}{n_{1}} = \frac{M_{2} V_{2}}{n_{2}} (N A O H)$
$\frac{1 \times V_{1}}{1} = \frac{1 \times 10}{2}; V_{1} = 5 m l$

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