How many mol of C atoms are present in 4×10−3 mol of glucose?
1 mol of glucose (C6H12O6) contains = 6 mol of C atoms ∴ 4×10−3 mol of glucose contains = 4×10−3×6=2.4×10−2 mol of C atoms
0.00024 in standard form will be-
(a) 24×10-5
(b) 2.4×103
(c) 2.4×10-4
(d) 24×10-3