How many mole of $A g C l$ would be obtained when $100$ moles of $0.1 C o C l_{3} .5 N H_{3}$ is treated with excess $A g N O_{3}$ ?

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Solution

The number of moles of $A g C l$ formed will depend upon the number of Chloride ions available in the coordinate compound. The number of Chloride ions satisfying the primary valency will only react with $A g N O_{3}$ to produce $A g C l$ .
$[C o (N H_{3})_{5} C l] C l_{2} + 2 A g N O_{3} \to [C o (N H_{3})_{5} C l] (N O_{3})_{2} + 2 A g C l$
Thus, 2 moles of $A g C l$ will be formed.

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