The electrolysis of the chlorine will takes place as follows :
Cl - + 1e - → 1/2 Cl2
Amount of Cl2 gas released; w = E It /F
I = 300 x 10-3 A
t = 60 s
F = 96500(for transfer of 1e-)
E = 35.5 g
w = 35.5 g x 300 x 10-3 A x 60 s / 96500
= 0.0066 g
Molar mass of Cl2 = 71 g
Moles of Cl2 deposited = 0.0066/71 g
= 9.32 x 10-5 moles
Molecules of Cl2 deposited = moles of Chlorine x NA
= 9.32 x 10-5 x 6.022 x 1023
= 5.61 x 1019