How many moles and how many grams of NaCl are present in 250ml of a 0.50M NaCl solution?

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Solution

Molar mass of NaCl = 23 + 35.5 = 58.5 g
Volume of solution = 250 mL
Molarity = 0.50 M
$M o l a r i t y = \frac{N u m b e r o f m o l e s}{V o l u m e i n l i t r e s} n = 0.5 \times 0.25 = 0.125 m o l e s n = \frac{G i v e n m a s s}{M o l a r m a s s} G i v e n m a s s = 0.125 \times 58.5 = 7.3125 g$

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