Question

How many moles are $9.033\times {10}^{24}$ atoms of helium?

• A. 13
• B. 15
• C. 22
• D. 16

Answer 1

The correct option is B

15

Helium can exist as a single atom due to its fully filled outermost shell(K shell).
$\therefore 6.022\times {10}^{23}$ atoms of helium= 1 mole

$9.033\times {10}^{24}$ atoms of helium = $\frac{9.033\times {10}^{24}}{6.022\times {10}^{23}}$
= 15moles.