Question

How many moles are there in 220 mg of $C{O}_2$?

• A. 5 moles
• B. 0.005 moles
• C. 5000 moles
• D. 10 moles

Answer 1

The correct option is B 0.005 moles

44 g of $C{O}_2$ = 1 mole
$220\times {10}^{-3}$ g of $C{O}_2=\frac{(220\times {10}^{-3})}{44}=5\times {10}^{-3}moles=.005moles$