How many moles are there in $28$ grams of $C O_{2}$ ?

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Solution

Since we have a given mass of $C O_{2}$ which is $28$ grams and also the chemical formula of carbon dioxide $(C O_{2})$ we could get the molecular mass of $C O_{2}$ by using the periodic table and then when we have those information we could now get the number of moles of $28$ grams of $C O_{2}$ .
GIVEN:
m of $C O_{2} = 28 g$
Molecular Weight of $C = 12 g / m o l$
$O = 16 g / m o l$
To get the molecular weight of $C O_{2}$ just add the molecular weights of each element and then multiply them by the number of atoms of each element. In this problem $C O_{2}$ , $C$ has only one atom and $O$ has two atoms in the compound. Therefore, getting molecular weight would be like this:
Molecular weight of $C O_{2} = 12 g / m o l + 2 (16 g / m o l) = 44 g / m o l o f C O_{2}$
Now we have the molecular weight of the compound and the given mass of compound which is $28 g$ . Therefore we could solve for the number of moles of $C O_{2}$ in $28 g$ of $C O_{2}$ .
Using Dimensional Analysis
$28 g C O_{2} \times 1 m o l C O_{2} / 44 g C O_{2} = 0.636 m o l$ of $C O_{2}$
For further readings use General Chemistry by Raymond Chang $10 t h$ ed chapter $3$ page $87$ and for dimensional analysis chapter $1$ page $27$

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