Question

How many moles of acetic anhydride will be required to form glucose pentaacetate from $2M$ of glucose?

• A. $2$
• B. $5$
• C. $10$
• D. $2.5$

Answer 1

The correct option is C $10$

When acetylated with acetic anhydride $(-O-\stackrel{\stackrel{O}{\parallel }}{C}-C{H}_3)$, glucose forms a pentaacetate.

The reaction is as follows:

In the given reaction, $1M$ of glucose is producing glucose pentaacetate i.e. it contains $5OAC$ group.

Therefore, $2M$ of glucose will produce glucose pentaacetate containing $10-OAC$ group.

Hence, $10$ moles of acetic anhydride will be required to form glucose pentaacetate from $2M$ of glucose.

Option C is correct.