How many moles of $A g (N H_{3})_{2}^{+}$ are needed to produce 11 moles of ammonia?
$. . . A g (N H_{3})_{2}^{+} \to . . . A g^{+} + . . . N H_{3}$

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5.5

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Solution

The correct option is D 5.5
The unbalanced chemical equation is $. . . A g (N H_{3})_{2}^{+} \to . . . A g^{+} + . . . N H_{3}$
Silver atoms are balanced. Balance ammonia molecules.
$A g (N H_{3})_{2}^{+} \to A g^{+} + 2 N H_{3}$
2 moles of ammonia will be produced by 1 mole of $A g (N H_{3})_{2}^{+}$
11 moles of ammonia will be produced by $\frac{11}{2} = 5.5$ mole of $A g (N H_{3})_{2}^{+}$

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