How many moles of aluminium sulphate, $A l_{2} (S O_{4})_{3}$ will contain $0.24$ mole of oxygen atoms?

2.0 \times 10^{2}

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2.0 \times 10^{- 2}

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3.0 \times 10^{3}

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1.5 \times 10^{- 2}

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Solution

The correct option is B $2 \times 10^{- 2} m o l e s$
A mole of aluminium sulphate contains 12 moles of oxygen

So $\frac{1}{12} \times 0.24$ moles of aluminium sulphate contains $0.24$ moles of oxygen

That is, $2 \times 10^{- 2}$ moles of aluminium sulphate contains $0.24$ moles of oxygen

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