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Standard XII

Chemistry

Frankland Halide Reaction

How many mole...

Question

How many moles of ${C_{2} O_{4}}^{2 -}$ ions will be oxidised by $1 m o l e {M n O_{4}}^{-}$ ?

1 / 2

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3 / 2

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5 / 2

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7 / 2

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Solution

The correct option is C $5 / 2$
We know the balanced chemical reaction between $C_{2} O_{4}^{- 2}$ and ${M n O_{4}}^{-}$ is
$5 N a_{2} C_{2} O_{4} + 2 K M n O_{4} + 8 H_{2} S O_{4} ⟶ K_{2} S O_{4} + 5 N a_{2} S O_{4} + 2 M n S O_{4} + 10 C O_{2} + 8 H_{2} O$
$5$ moles of $C_{2} O_{4}^{- 2}$ oxidizes $⟶ 2$ moles of $K M n O_{4}$
$x ⟵ 1$ mole of $K M n O_{4}$
$\Rightarrow x = \frac{1 \times 5}{2} = 5 / 2$ moles of $C_{2} O_{4}^{- 2}$

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