How many moles of calcium carbonate CaCO 3 are present in 10 g of the substance - Ca -40 u - C -12 u - O -16 u

Mass of calcium carbonate = 10g Molecular mass of calcium carbonate = (1 times; 40) + (1 times; 12) + (3 times; 16) = 100g Number of moles in 100g of c ...

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Standard IX

Chemistry

Atomic Mass and Atomic Mass Unit

How many mole...

Question

How many moles of calcium carbonate (CaCO₃) are present in 10 g of the substance ? (Ca = 40 u ; C = 12 u ; O = 16 u)

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Solution

Mass of calcium carbonate = 10g
Molecular mass of calcium carbonate = (1 × 40) + (1 × 12) + (3 × 16) = 100g
Number of moles in 100g of calcium carbonate = 1 mole
Therefore, number of moles in 10g of calcium carbonate is 0.1.

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How many moles of calcium carbonate (CaCO3) are present in 10 g of the substance ? (Ca = 40 u ; C = 12 u ; O = 16 u)

Mass of calcium carbonate = 10g Molecular mass of calcium carbonate = (1 × 40) + (1 × 12) + (3 × 16) = 100g Number of moles in 100g of calcium carbonate = 1 mole Therefore, number of moles in 10g of calcium carbonate is 0.1.

How many moles of calcium carbonate (CaCO₃) are present in 10 g of the substance ? (Ca = 40 u ; C = 12 u ; O = 16 u)

Mass of calcium carbonate = 10g
Molecular mass of calcium carbonate = (1 × 40) + (1 × 12) + (3 × 16) = 100g
Number of moles in 100g of calcium carbonate = 1 mole
Therefore, number of moles in 10g of calcium carbonate is 0.1.