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Mole Concept and Avogadro's Number

How many mole...

Question

How many moles of $C r$ are there in $85 g$ of $C r_{2} S_{3}$ ? ( $C r = 52, S = 32$ )

A

0.75

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B

0.85

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C

0.50

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D

0.40

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Solution

The correct option is A $0.85$
Molar mass of $C r_{2} S_{3} = (2 \times 52) + (3 \times 32) = 104 + 96 = 200 g$
Therefore, $200 g$ of $C r_{2} S_{3}$ has $(2 \times 52) g$ of $C r$
So, $85 g$ of $C r_{2} S_{3}$ will have $= \frac{85 \times 2 \times 52}{200} = 44.2 g$
Moles of $C r$ in $C r_{2} S_{3} = \frac{44.2 g}{104 g} = 0.85$

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