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Charge and Current

How many mole...

Question

How many moles of electrons will together contribute to the charge of 289500 coulomb?

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Solution

1 mole of electrone contribute to the charge of 1 F = 96500 C
1 C charge = $\frac{1}{96500}$ F
289500 C charge = $\frac{1}{96500}$ 289500 F
=3F
3 mole of electrone will together contribute to the charge of 289500 C

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