Question

How many moles of electrons will weigh one kilogram?

• A. $6.023\times {10}^{23}$
• B. $\frac{1}{9.108}\times {10}^{31}$
• C. $\frac{6.023}{9.108}\times {10}^{54}$
• D. $\frac{1}{9.108\times 6.023}\times {10}^8$

Answer 1

The correct option is D $\frac{1}{9.108\times 6.023}\times {10}^8$

Mass of one mole of electron $=9.108\times {10}^{-31}\times 6.023\times {10}^{23}$Kg
Then no of mole of $e^{-}$ in $1$kg $=\frac{1}{9.108\times 6.023\times {10}^{-8}}$
$=\frac{1}{9.108\times 6.023}\times {10}^8$ mole of $e^{-}$.