wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many moles of excess reagent are left by the reaction of 6.4 mol of HCl and 3.5 mol of Zn?
The reaction that takes place is:
Zn+2HClZnCl2+H2

A
0.30 mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3.45 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4.90 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.54 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.30 mol
Zn+2HClZnCl2+H2
To find limiting reagent:
For Zn=3.51=3.5
For HCl=6.42=3.2
From above, we can say that HCl is the limiting reagent and Zn is the excess reagent.
To find the number of moles of Zn required to consume 6.4 mol HCl:

6.4 mol of HCl×1 mol of ZnCl22 mol of HCl=3.2 mol of Zn
Number of moles of the excess reagent left = 3.5 - 3.2 = 0.3 mol

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon