You visited us 4 times! Enjoying our articles? Unlock Full Access!

Molarity

How many mo...

Question

How many $m o l e s$ of glucose ( $C_{6} H_{12} O_{6}$ ) should be dissolved into a solution with a total volume of $0.500 L$ to produce a $1 M$ glucose solution?

1

mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

mol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.25

mol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $0.5$ mol
Molarity of Glucose $= \frac{No. of moles of Glucose}{Volume of solution in Litres}$
$\Rightarrow$ No. of moles of Glucose $= (Molarity) \times V o l u m e = 1 \times 0.5 = 0.5 m o l e s$

Suggest Corrections

Similar questions

(C_{6} H_{12} O_{6})

^{- 1}

0.625 g

(C_{6} H_{12} O_{6})

102.8 g

= 273 K

K_{f}

= 1.87 K

k g

{m o l}^{- 1}

C = 12

H = 1

O = 16

540 g

(C_{6} H_{12} O_{6})

Δ H_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b} [C_{6} H_{12} O_{6} (s)] = - 2816 k J / m o l

Δ H_{f}^{o}

{C O}_{2} (g) = - 393.5 k J / m o l

Δ H_{f}^{o}

H_{2} O (l) = - 285.9 k J / m o l

10 %

1

Join BYJU'S Learning Program