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Molarity

How many mo...

Question

How many $m o l e s$ of glucose ( $C_{6} H_{12} O_{6}$ ) should be dissolved into a solution with a total volume of $0.500 L$ to produce a $1 M$ glucose solution?

1

mol

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24

mol

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0.5

mol

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0.25

mol

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Solution

The correct option is D $0.5$ mol
Molarity of Glucose $= \frac{No. of moles of Glucose}{Volume of solution in Litres}$
$\Rightarrow$ No. of moles of Glucose $= (Molarity) \times V o l u m e = 1 \times 0.5 = 0.5 m o l e s$

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Similar questions

(C_{6} H_{12} O_{6})

^{- 1}

0.625 g

(C_{6} H_{12} O_{6})

102.8 g

= 273 K

K_{f}

= 1.87 K

k g

{m o l}^{- 1}

C = 12

H = 1

O = 16

540 g

(C_{6} H_{12} O_{6})

Δ H_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b} [C_{6} H_{12} O_{6} (s)] = - 2816 k J / m o l

Δ H_{f}^{o}

{C O}_{2} (g) = - 393.5 k J / m o l

Δ H_{f}^{o}

H_{2} O (l) = - 285.9 k J / m o l

10 %

1

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