How many moles of glucose is present in $100$ gram of glucose $(C_{6} H_{12} O_{6})$ ?

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Solution

Molecular mass of $C_{6} H_{12} O_{6} = (12 \times 6) + 12 + (16 \times 6)$
= $180 g$
$∵ n = \frac{M a s s}{M o l a r m a s s}$
$∴$ Moles of $C_{6} H_{12} O_{6} = \frac{100 g}{180 g}$
= $0.56$ $m o l e s$
$∴$ No. of moles of $C_{6} H_{12} O_{6}$ is $0.56$ $m o l e s$

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