You visited us 2 times! Enjoying our articles? Unlock Full Access!

Hydrogen Peroxide

How many mole...

Question

How many moles of $H_{2} O_{2}$ are present in 2 litres of 6.8% w/v $H_{2} O_{2}$ solution?

Open in App

Solution

$6.8$ % (w/v)= $\frac{6.8 g o f H_{2} O_{2}}{100 m l o f w a t e r} \times 100$
$∴$ In $2$ litres, $6.8 \times 2 \times 10 g$ of $H_{2} O_{2}$ will be present.
$∴$ Mass of $H_{2} O_{2} = 6.8 \times 2 \times 10 = 136 g$

$∴$ Moles of $H_{2} O_{2} = \frac{136}{34} = 4$ moles

Suggest Corrections

Similar questions

H_{2} O_{2}

C l O_{2}

H_{2} O_{2}

O_{2}

C l^{-}

H_{2} O_{2}

1

C l O_{2}

H_{2} {SO}_{4}

H_{2} O_{2}

10 V

H_{2} O_{2}

273 K

H_{2} O_{2}

10 l i t r e

O_{2}

273 K

H_{2} O_{2}

H_{2} O_{2} (a q) \to H_{2} O (l) + \frac{1}{2} O_{2} (g)

H_{2} O_{2}

H_{2} O_{2}

H_{2} O

H_{2} O_{2}

O_{2}

2

∴, Normality of H_{2} O_{2} Solution = 2 \times Molarity of H_{2} O_{2} Solution

11.2 V H_{2} O_{2}

15 %

H_{2} O_{2}

Join BYJU'S Learning Program