Question

How many moles of $H_2{O}_2$ is oxidised by $0.5$ mol $K_{2}C{r}_2{O}_7$ in acidic medium?

• A. $2$
• B. $3$
• C. $1.5$
• D. $6$

Answer 1

The correct option is C $1.5$

Reaction of $H_2{O}_2$ with $K_{2}C{r}_2{O}_7$ is as follows:

$K_{2}C{r}_2{O}_7+3H_2{O}_2+4H_{2}S{O}_4\to C{r}_2(S{O}_4{)}_3+K_{2}S{O}_4+7H_{2}O+3O_2$

Since, $1$ mole of $K_{2}C{r}_2{O}_7$ reacts with 3 moles of $H_2{O}_2$.

Therefore, $0.5$ mole of $K_{2}C{r}_2{O}_7$ reacts with $1.5$ moles of $H_2{O}_2$.