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Question

How many moles of HCl must be removed from 1 liter of aqueous HCl solution to change its pH from 2 to 3?

A
1
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B
0.02
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C
0.009
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D
0.01
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Solution

The correct option is D 0.009
HCl is the strong acid and dissociates completely.
HClH++Cl
PH=logH+
For PH=2=>102mol/L
For PH=3=>103mol/L
the number of moles of HCl must be removed from 1 LiterHCl=102103=0.009moles.

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