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Half life

How many mole...

Question

How many moles of helium are produced when one mole of $_{92}^{238} U$ disintegrates into $_{82}^{206} P b$ ?

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Solution

Radioactive change is
$_{92}^{238} U ⟶_{82}^{206} P b$
Decrease in mass $= (238 - 206) = 32$
Let the number of $α$ -particles emitted be $x$ .
$4 x = 32$
$x = 8$
Thus, $8$ moles of helium are produced when one mole of $_{92}^{238} U$ disintegrates into $_{82}^{206} P b$ .

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