How many moles of hydrogen are present in 20 g of 85 - pure N aHCO 3-A- 1B- 0-202C- 0-303D- 0-404

The correct option is B 0.202 Molecular mass of NaHCO_3 = 23 + 1 + 12 + (3 × 16) = 84 u Now, for purity, 85% of given substance is NaHCO_3. ∴ Amount of NaHCO_3 ...

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Standard XII

Chemistry

Atomic Number and Mass Number

How many mole...

Question

How many moles of hydrogen are present in 20g of $85 %$ pure $N a H C O_{3}$ .

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0.202

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0.303

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0.404

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Solution

The correct option is B
0.202

Molecular mass of $N a H C O_{3}$ = $23 + 1 + 12 + (3 \times 16) = 84 u$

Now, for purity, $85 %$ of given substance is $N a H C O_{3}$ .

$∴$ Amount of $N a H C O_{3}$ present = $\frac{85}{100} \times 20 = 17 g$

From the molecular mass, $84 g$ = $1 m o l e o f H$
Therefore $17 g$ = $0.202 m o l e o f H$

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How many moles of hydrogen are present in 20g of 85% pure NaHCO3.

The correct option is B 0.202 Molecular mass of NaHCO3 = 23+1+12+(3× 16)=84u Now, for purity, 85% of given substance is NaHCO3. ∴ Amount of NaHCO3 present = 85100 ×20=17g From the molecular mass, 84g = 1 mole of H Therefore 17g = 0.202 mole of H

How many moles of hydrogen are present in 20g of $85 %$ pure $N a H C O_{3}$ .