How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?
1
2
3
4
K2Cr2O7+4H2SO4→K2SO4+Cr2(SO4)3+4H2O+3[O]
[2KI+H2SO4+[O]→K2SO4+I2+H2O]×3
K2Cr2O7+7H2SO4+6KI→4K2SO4+3I2+Cr2(SO4)3+7H2O