Question

How many moles of 'iodine' are liberated when $2$ moles of $KMn{O}_4$ react with $KI$ in acidic medium?

Answer 1

In acidic medium
$2Mn{O}_4^{-}+16H^{+}+10I^{-}\to 2M{n}^{2+}+8H_{2}O+S{I}_2$
According to above reaction $2$ moles of $KMn{O}_4$ gives $5$ mole $I_2$.