Question

How many moles of iron can be made from $F{e}_2{O}_3$ by the use of 16 mol of CO in the following reaction?

$F{e}_2{O}_3$ + 3CO $\to$ 2Fe +3$C{O}_2$

• A. 11.23
• B. 10.67
• C. 15.2
• D. 10.69

Answer 1

The correct option is B

10.67

$F{e}_2{O}_3$ + 3CO $\to$ 2Fe +3$C{O}_2$

3 moles of CO gives 2 moles of Fe on reaction with $F{e}_2{O}_3$

1 mole of CO gives $\frac{2}{3}$ moles of Fe on reaction with $F{e}_2{O}_3$

16 moles of CO gives = ($\frac{2}{3}\times$ 16) moles of Fe

= 10.67

So, 10.67 moles of iron can be made from $F{e}_2{O}_3$ by the use of 16 mol of CO.