How many moles of iron can be made from the excess of $F e_{2} O_{3}$ using 16 mol of carbon monoxide in the following reaction?
$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

11.22

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15.38

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10.67

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 10.67
The balanced equation is:
$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

3 mol of $C O$ are used to produce 2 mol $F e$ .
16 mol of $C O$ will be used to produce = $\frac{2}{3} \times 16$ = 10.67 mol of $F e$

Suggest Corrections

Similar questions

F e_{2} O_{3}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

How many moles of iron can be made from $F e_{2} O_{3}$ by the use of 16 mol of CO in the following reaction?

$F e_{2} O_{3}$ + 3CO $\to$ 2Fe +3 $C O_{2}$

{F e}_{2} O_{3} + 3 C O ⟶ 2 F e + 3 C O_{2}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program