Question

How many moles of $KI$ are needed to produce $0.4$ moles of $K_{2}Hg{I}_4$ ?

• A. $0.4$
• B. $0.8$
• C. $3.2$
• D. $1.6$

Answer 1

The correct option is D $1.6$

$Hg{Cl}_2+4KI⟶2KCl+K_{2}Hg{I}_4$

$\therefore 4moles$ of $KI$ give $1mole$ of $K_{2}Hg{I}_4$

Thus, $0.4moles$ of $K_{2}Hg{I}_4$ require $\frac{0.4\times 4}{1}moles$ of $KI$ i.e., $1.6moles$ of $KI$.