Question

How many moles of $KI$ are required to produce $0.4$ moles of $K_{2}Hg{I}_4$?

• A. 0.4
• B. 0.8
• C. 3.2
• D. 1.6

Answer 1

Answer: (D)

1.6

$HgC{l}_2+4KI\to 2KCl+K_{2}Hg{I}_4$

From the above equation,

1 mole of $K_{2}Hg{I}_4$ requires 4 moles of $KI$

0.4 moles of $K_{2}Hg{I}_4$ requires $0.4\times 4=1.6$ molesof $KI$

$\therefore$ To produce 0.4 moles of $K_{2}Hg{I}_4$, 1.6 moles of $KI$ is required