Question

How many moles of ${KMnO}_4$ are reduced by $1$ mole of ferrous oxalate in acidic medium?

• A. $\frac{1}{5}$
• B. $\frac{5}{3}$
• C. $\frac{1}{3}$
• D. $\frac{3}{5}$

Answer 1

Answer: (D)

$\frac{3}{5}$

In acidic medium,

$3{KMnO}_4+5Fe{C}_2{O}_4+24H^{+}⟶3K^{+}+3{Mn}^{2+}+5{Fe}^{+3}+10{CO}_2+12H_{2}O$

Here, $3$ moles of ${KMnO}_4$ reduces $5$ moles of ${FeC}_2{O}_4$.

$\therefore \frac{3}{5}$ moles of ${KMnO}_4$ reduces $1$ mole of ${FeC}_2{O}_4$.

Hence, option $D$ is correct.