Question

How many moles of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ will be produced when one mole of propane is completely burnt in ${\mathrm{O}}_2$ gas?

Answer 1

1. Propane, ${\mathrm{C}}_3{\mathrm{H}}_8$, a fuel used in many outdoor grills, burns in oxygen to produce Carbon dioxide gas, ${\mathrm{CO}}_2$, and Water vapor, ${\mathrm{H}}_2\mathrm{O}$, as shown in the reaction below:
2. Reaction: $$\begin{gathered} {\mathrm{C}}_3{\mathrm{H}}_8\left(\mathrm{g}\right)+5{\mathrm{O}}_2\left(\mathrm{g}\right)\to 3{\mathrm{CO}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right) \\ \left(\mathrm{Propane}\right)\left(\mathrm{Oxygen}\right)(\mathrm{Carbon}\mathrm{dioxide})\left(\mathrm{Water}\right) \end{gathered}$$
3. Here, every one mole of ${\mathrm{C}}_3{\mathrm{H}}_8$(Propane) will react with 5 moles of ${\mathrm{O}}_2$ (Oxygen) to yield or produce 3 moles of ${\mathrm{CO}}_2$( Carbon dioxide) and 4 moles of ${\mathrm{H}}_2\mathrm{O}$ (Water).
4. Hence, when 1 mole of Propane is completely burnt in air 3 moles of Carbon dioxide is produced.

Therefore, 3 moles of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ will be produced when one mole of propane is completely burnt in ${\mathrm{O}}_2$ gas.