How many moles of methane are required to produce 22 g of $C O_{2} (g)$ after combustion ?

0.5 mol

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1 mol

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0.25 mol

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1.5 mol

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Solution

The correct option is A 0.5 mol
CH $_{4}$ +2O $_{2}$ $\to$ CO $_{2}$ +2H $_{2}$ O
Gram molecular mass of $C O_{2}$ =12+2(16)
$=$ 44

44g CO $_{2}$ produced by 16 g CH $_{4}$

1 g CO $_{2}$ produced by $\frac{16}{44}$ of CH $_{4}$

22g CO $_{2}$ produced by $\frac{16}{44} \times 22 g = 8 g$ of CH $_{4}$

Number of moles of CH $_{4}$ required = $\frac{8}{16}$ =0.5 moles.

Hence, the correct option is $A$

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