Question

How many moles of $N_2$ are needed to produce 8.2 moles of $N{H}_3$ by reaction with $H_2$?

• A. 4.1
• B. 6.2
• C. 8.2
• D. 7.1

Answer 1

The correct option is A

4.1

$N_2$ + $H_2$ = $N{H}_3$..................(i)

Balancing the Equation (i), we get

$N_2$ + 3 $H_2$ = 2$N{H}_3$

1 mole of $N_2$ 3 moles of $H_2$ 2 moles of $N{H}_3$

So,

2 moles of $N{H}_3$ is produced by 1 mole of $N_2$

1 mole of $N{H}_3$ is produced by 0.5 mole of $N_2$

8.2 moles of $N{H}_3$ is produced by = 0.5 $\times$ 8.2 = 4.1 moles of $N_2$

So, 4.1 moles of $N_2$ is required to produce 8.2 moles o f $N{H}_3$.