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Question

How many moles of NaOH must be removed from one litre of aqueous solution to change its pH from 12 to 11?

A
0.009
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B
0.01
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C
0.02
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D
0.1
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Solution

The correct option is A 0.009
InitialFinalpH=12pH=11[H+]=1012M[H+]=1011M[OH]=102M[OH]=103M
Initial number of moles of OH=102
Final number of moles of OH=103
So, number of moles of OH removed = [0.01 - 0.001]
= 0.009

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