How many moles of NaOH must be removed from one litre of aqueous solution to change its pH from 12 to 11?
A
0.009
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B
0.01
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C
0.02
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D
0.1
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Solution
The correct option is A 0.009 InitialFinalpH=12pH=11[H+]=10−12M[H+]=10−11M[OH−]=10−2M[OH−]=10−3M Initial number of moles of OH−=10−2 Final number of moles of OH−=10−3 So, number of moles of OH− removed = [0.01 - 0.001] = 0.009