How many moles of $N i (C O)_{4}$ could be obtained from the CO produced by the reaction of 75.0 g of carbon?
[Assume 100% reaction and 100% recovery in both steps and molar mass of Ni = 59 g/mol].

6.25

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1.5625

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3.125

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Solution

The correct option is B 1.5625
1 mole of $N i (C O)_{4}$ will require 4 moles of C.

This corresponds to $4 \times 12 = 48 g$ of C.

Thus, 75.0 g of carbon will give $\frac{1}{48} \times 75.0 = 1.5625 m o l e s$

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