How many moles of nitric acid are required to convert $1 m o l$ of sulfur to sulfuric acid?

10

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4

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48

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20

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Solution

The correct option is C $48$
$1 m o l$ of sulfur $(S_{8})$ requires $48 m o l$ of concentrated nitric acid $(H N O_{3})$ . The reaction is: $S_{8} + 48 H N O_{3} \to 8 H_{2} S O_{4} + 48 N O_{2} + 16 H_{2} O$

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M g C O_{3}

1 m o l

K M n O_{4}

K I

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