How many moles of nitrogen are required to produce 8.2 mol of ammonia on a reaction with an excess of hydrogen?

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Solution

The balanced chemical equation is:
$N_{2} + 3 H_{2} \to 2 N H_{3}$
From stoichiometry,
2 mol of $N H_{3}$ is produced from 1 mol of $N_{2}$ .
8.2 mol of $N H_{3}$ will be produced from = $\frac{1}{2} \times 8.2$ = 4.1 mol of $N_{2}$

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