How many moles of $O_{2}$ will be liberated by one mole by $C r O_{5}$ is the following reaction?
$C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}$

4.5

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2.5

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1.25

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None of the above

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Solution

The correct option is D None of the above
The balanced reaction is as follows:
$2 C r O_{5} + 3 H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + 3 H_{2} O + \frac{7}{2} O_{2}$
$2$ mol $C r O_{5} = \frac{7}{2}$ mol of $O_{2}$
$1$ mol $C r O_{5} = \frac{7}{4}$ mol of $O_{2}$

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