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Stoichiometric Calculations

How many mole...

Question

How many moles of oxygen are required to react completely with $24$ g of $C H_{4}$ ?

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Solution

The balanced chemical equation for the complete consumption of methane is as given below:
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
$24$ g of methane corresponds to $\frac{24 g}{16 g / m o l} = 1.5$ mol.
They will require $\frac{2}{1} \times 1.5 m o l = 3.0$ mol.

Thus, $3$ moles of oxygen are required to react completely with $24$ g of methane.

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