How many moles of oxygen atoms are present in 1 mole of KMno4

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Solution

Dear Student,

mass of Oxygen in KMnO₄= 64 gm
16 gm = 1mole Oxygen
64 gm = $\frac{1}{16} \times 64$ = 4 moles
So, 4 moles O are present in KMnO₄

Regards!

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How many moles of oxygen atoms are present in 1 mole of KMno4

Dear Student, mass of Oxygen in KMnO​4= 64 gm 16 gm = 1mole Oxygen 64 gm =116×64= 4 moles So, 4 moles O are present in KMnO4 Regards!

Dear Student,

mass of Oxygen in KMnO₄= 64 gm
16 gm = 1mole Oxygen
64 gm = $\frac{1}{16} \times 64$ = 4 moles
So, 4 moles O are present in KMnO₄

Regards!