How many moles of oxygen atoms is present in 80 - pure 20 g of CO 2 -A- 0-73B- 0-25C- 1D- 0-5

The correct option is A 0.73 80% pure 20g of CO_2 has (20 ×80/100)g of CO_2 i.e., 16g of CO_2 is present. For CO_2, 44g of CO_2 = 32g of O_2 = 2 moles of O. ∴ ...

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Standard XII

Chemistry

Atomic Number and Mass Number

How many mole...

Question

How many moles of oxygen atoms is present in $80 %$ pure 20g of $C O_{2}$ ?

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0.5

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0.25

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0.73

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Solution

The correct option is D
0.73

80 $%$ pure 20g of $C O_{2}$ has $(20 \times \frac{80}{100}) g$ of $C O_{2}$ i.e., 16g of $C O_{2}$ is present.

For $C O_{2}$ , 44g of $C O_{2}$ = $32 g$ of $O_{2}$ = 2 moles of $O$ .

$∴$ $16 g$ of $C O_{2}$ = $(\frac{16 \times 2}{44})$ moles of O

= 0.727 moles of O

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How many moles of oxygen atoms is present in 80% pure 20g of CO2?

The correct option is D 0.73 80% pure 20g of CO2 has (20×80100)g of CO2 i.e., 16g of CO2 is present. For CO2, 44g of CO2 = 32g of O2 = 2 moles of O. ∴ 16g of CO2 = (16×244) moles of O = 0.727 moles of O

How many moles of oxygen atoms is present in $80 %$ pure 20g of $C O_{2}$ ?