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Mole Concept and Avogadro's Number

How many mole...

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How many moles of oxygen gas will be evolved when 24.5 g of KClO3 is heated for complete decomposition? (molar mass of KClO3 is 122.5g)

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Q. Oxygen is prepared by catalytic; decomposition of potassium chlorate

(K C l O_{3})

. Decomposition, of potassium chlorate gives potassium chloride

(K C l)

(O_{2})

. How many moles and how many grams of

K C l O_{3}

are required to produce 2.4 mole

O_{2}

{K C l O}_{3}

on decomposition yielded

448 m L

of oxygen gas at STP. then the weight of

{K C l O}_{3}

originally taken was:

Q. In the reaction,

2 K C l O_{3} ⟶ 2 K C l + 3 O_{2}

when 36.75 g of

K C l O_{3}

is heated, the volume of oxygen evolved at NTP will be:

0.05 g

of a commercial sample of

K C l O_{3}

on decomposition liberated just sufficient oxygen for complete oxidation of

20 m L

C O

27^{o} C

750 m m

pressure. Calculate

%

K C l O_{3}

2

K C l O_{3}

by decomposition of all the

K C l O_{3}

, how many liters of

O_{2}

can be produced at STP?

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