Question

How many moles of potassium chlorate to be heated to produce $11.2$ L of oxygen at NTP?

• A. $\frac{1}{2}$ mole
• B. $\frac{1}{3}$ mole
• C. $\frac{1}{4}$ mole
• D. $\frac{2}{3}$ mole

Answer 1

The correct option is B $\frac{1}{3}$ mole

At NTP, 11.2 L of oxygen corresponds to $\frac{11.2}{22.4}=0.5mol$

$2KCl{O}_3\stackrel{heat}{\to }2KCl+3O_2$

Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen.

Thus, $\frac{2}{3}\times 0.5=\frac{1}{3}$ moles of potassium chlorate on heating gives 11.2 L of oxygen at NTP.

Hence, the correct option is $B$