How many moles of sodium chloride are present in 250mL of a 0.50 M NaCI solution?
The correct option is A 0.125 mol
given data :
Volume =250 ml
Molarity =0.50 M
Molarity =No of MolesVolume
No. of Moles = Molarity ×Volume(L)
=0.5×0.25 =0.125 mol