How many moles of sulfate ions are in $200 m L$ of a $2 M$ sodium sulfate solution?

0.2 m o l

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0.4 m o l

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0.6 m o l

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0.8 m o l

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1.0 m o l

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Solution

The correct option is A $0.4 m o l$
$N a_{2} S O_{4} \to 2 N a^{2 +} + S O_{4}^{2 -}$
The number of moles of sulfate ions $=$ number of moles of sodium sulfate $= 2 m o l / L \times \frac{200 m L}{1000 m L / L} = 0.4 m o l$ .

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