How many moles of tetrahedral voids present in 2 cm long iron cube assuming cubic shape is FCC unit cell? Density of iron is 7.0 g/cc. Its atomic mass is 56 amu.
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Solution
As we know, Mass of cube =V×d=8×7.0=56 g Moles of atom =8×7.056=1.0 mol Moles of tetrahedral voids = twice the of number of atoms =2×1.0=2 mol