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Question

How many moles of CaCO3 are present in 500 g of CaCO3?
Gram atomic masses Ca, C, and O are 40, 12, and 16 respectively.

A
10
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B
8
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C
5
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D
6
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Solution

The correct option is C 5

Given mass of CaCO3 = 500 g
Gram molecular mass of CaCO3 =
Atomic mass of Ca + Atomic mass of C + 3 × Atomic mass of O = 40 + 12 + 3 × 16 = 100 g

We know that, number of moles
= Given massGram molecular mass

After inserting the given values in the above equation we have, moles of CaCO3 = 500100 = 5 moles

Therefore, number of moles present in 500 g of CaCO3 is 5.


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