How many moles of CaCO3 are present in 500 g of CaCO3?
Gram atomic masses Ca, C, and O are 40, 12, and 16 respectively.
Given mass of CaCO3 = 500 g
Gram molecular mass of CaCO3 =
Atomic mass of Ca + Atomic mass of C + 3 × Atomic mass of O = 40 + 12 + 3 × 16 = 100 g
We know that, number of moles
= Given massGram molecular mass
After inserting the given values in the above equation we have, moles of CaCO3 = 500100 = 5 moles
Therefore, number of moles present in 500 g of CaCO3 is 5.